16x^2+5x=71

Solution for 16x^2+5x=71 equation:

16x^2+5x=71

We move all terms to the left:

16x^2+5x-(71)=0

a = 16; b = 5; c = -71;
Δ = b2-4ac
Δ = 52-4·16·(-71)
Δ = 4569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{4569}}{2*16}=\frac{-5-\sqrt{4569}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{4569}}{2*16}=\frac{-5+\sqrt{4569}}{32}
$